z=(1-(3+i)^2(1-2i))/(2i^{77)-i^{726}}

Lösung

z = \frac{1 - ( 3 + i ) ^{2} ( 1 - 2 i )}{2 i ^{77} - i ^{726}}

z = \frac{1}{5} + i \frac{48}{5}

Schritte zur Lösung

z = \frac{1 - ( 3 + i ) ^{2} ( 1 - 2 i )}{2 i ^{77} - i ^{726}}

Vereinfache

\frac{1 - ( 3 + i ) ^{2} ( 1 - 2 i )}{2 i ^{77} - i ^{726}} : \frac{1}{5} + i \frac{48}{5}

z = \frac{1}{5} + i \frac{48}{5}

5 (9 - A) = 20 + 3 + 6 A

\frac{x}{3} = \frac{3}{4}

\frac{3 m}{4} - \frac{6}{5} = \frac{9}{4} - \frac{6 m}{3}

\frac{1}{4} - \frac{3 x - 2}{8} = \frac{2 x + 3}{6}

\frac{x}{2} - 4 = \frac{x}{3} + 1