m=((1+2i)(3-i))/((2+i))

Lösung

m = \frac{( 1 + 2 i ) ( 3 - i )}{( 2 + i )}

m = 3 + i

Schritte zur Lösung

m = \frac{( 1 + 2 i ) ( 3 - i )}{( 2 + i )}

Vereinfache

\frac{( 1 + 2 i ) ( 3 - i )}{2 + i} : 3 + i

m = 3 + i

- \frac{1}{100} x + 115 = \frac{87}{100} x + 11

so l v e f or x, y = f (x - 3)

4 x - 3 (x + 5) = x - 18

2 x + 9 = 5 x

12 x = 24