v^2=-16

Lösung

v^{2} = - 16

v = 4 i, v = - 4 i

Schritte zur Lösung

v^{2} = - 16

Für

x^{2} = f (a)

sind die Lösungen

x = f (a), - f (a)

v = - 16, v = - - 16

- 16 = 4 i

- - 16 = - 4 i

v = 4 i, v = - 4 i

\frac{4}{3} - \frac{1}{2} x \geq \frac{1}{6} + x

x^{2} - 6 x - 49 = 6 x

2 x^{2} - 5 x + 2 > 0

s im pl i f y (3 x^{2} \cdot 6 x^{4})^{- 3}

∣ T - 45 ∣ \leq 26