What is the answer to (x-1)/2 =(x-2)/3+(x-3)/4 ?

The answer to (x-1)/2 =(x-2)/3+(x-3)/4 is x=11

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(x-1)/2 =(x-2)/3+(x-3)/4

\frac{x - 1}{2} = \frac{x - 2}{3} + \frac{x - 3}{4}

x = 11

Solution steps

\frac{x - 1}{2} = \frac{x - 2}{3} + \frac{x - 3}{4}

Multiply by LCM

6 (x - 1) = 4 (x - 2) + 3 (x - 3)

Expand

6 (x - 1) : 6 x - 6

Expand

4 (x - 2) + 3 (x - 3) : 7 x - 17

6 x - 6 = 7 x - 17

Move

6

to the right side

6 x = 7 x - 11

Move

7 x

to the left side

- x = - 11

Divide both sides by

- 1

x = 11

x = \frac{5 + - 49}{6}

9 x + 5 = x - 3

\frac{5}{6} + \frac{x}{2} = \frac{3 x}{5} + \frac{2}{3}

4 + \frac{( 40 - x )}{130} - \frac{13 x}{1932} = 0

x, x + y = 200

What is the answer to (x-1)/2 =(x-2)/3+(x-3)/4 ?
The answer to (x-1)/2 =(x-2)/3+(x-3)/4 is x=11
Solve for x: (x-1)/2 =(x-2)/3+(x-3)/4
The solution is x=11