((x+1)(x-2)^2(x)^2)/((x+6)^2(x+3)^2)<= 0

解答

\frac{( x + 1 ) ( x - 2 ) ^{2} ( x ) ^{2}}{( x + 6 ) ^{2} ( x + 3 ) ^{2}} \leq 0

x < - 6 or - 6 < x < - 3 or - 3 < x \leq - 1 or x = 0 or x = 2

间隔符号

(- \infty, - 6) \cup (- 6, - 3) \cup (- 3, - 1] \cup x = 0 \cup x = 2

求解步骤

\frac{( x + 1 ) ( x - 2 ) ^{2} x ^{2}}{( x + 6 ) ^{2} ( x + 3 ) ^{2}} \leq 0

确定区间

x < - 6 or - 6 < x < - 3 or - 3 < x \leq - 1 or x = 0 or x = 2

5 x = 6 x - 7

- x - 3 < 0

∣ x + 9 ∣ = 4

\frac{( 25 - a )}{7} = 3

- 7 f - 5 (- 8 f + 10) < - 4 f - 3 - 3