faktorisieren x^4+x^3-3x^2-5x-2

Lösung

faktorisieren

x^{4} + x^{3} - 3 x^{2} - 5 x - 2

(x + 1)^{3} (x - 2)

Schritte zur Lösung

x^{4} + x^{3} - 3 x^{2} - 5 x - 2

Wende den rationalen Nullstellentest an

= (x + 1) \frac{x ^{4} + x ^{3} - 3 x ^{2} - 5 x - 2}{x + 1}

\frac{x ^{4} + x ^{3} - 3 x ^{2} - 5 x - 2}{x + 1} = x^{3} - 3 x - 2

= (x + 1) (x^{3} - 3 x - 2)

Faktorisiere

x^{3} - 3 x - 2 : (x + 1) (x + 1) (x - 2)

= (x + 1) (x + 1) (x + 1) (x - 2)

Wende Exponentenregel an:

aaa = a^{3}

(x + 1) (x + 1) (x + 1) = (x + 1)^{3}

= (x + 1)^{3} (x - 2)

f a c t or a - 8 a \cdot b^{3}

s im pl i f y f (x) - 4 x^{2} + 100 x - 60

s im pl i f y x + \frac{y}{x ^{2}} - y + c - 2 \frac{y}{3} x^{2} - 3 y

s im pl i f y (\frac{- a}{c})^{2} - 2 (\frac{b}{c})

f a c t or 4 a^{4} - 5 a^{2} + 1