What is (x-1/2 y+1/3 z)^2 ?

The solution to (x-1/2 y+1/3 z)^2 is -xy+(2xz-yz)/3+x^2+(y^2)/4+(z^2)/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x-1/2 y+1/3 z)^2

simplify

(x - \frac{1}{2} y + \frac{1}{3} z)^{2}

- x y + \frac{2 x z - yz}{3} + x^{2} + \frac{y ^{2}}{4} + \frac{z ^{2}}{9}

Solution steps

(x - \frac{1}{2} y + \frac{1}{3} z)^{2}

\frac{1}{2} y = \frac{y}{2}

\frac{1}{3} z = \frac{z}{3}

= (x - \frac{y}{2} + \frac{z}{3})^{2}

(x - \frac{y}{2} + \frac{z}{3})^{2} = (x - \frac{y}{2} + \frac{z}{3}) (x - \frac{y}{2} + \frac{z}{3})

= (x + \frac{z}{3} - \frac{y}{2}) (x + \frac{z}{3} - \frac{y}{2})

Expand

(x - \frac{y}{2} + \frac{z}{3}) (x - \frac{y}{2} + \frac{z}{3}) : - x y + \frac{2 x z - yz}{3} + x^{2} + \frac{y ^{2}}{4} + \frac{z ^{2}}{9}

= - x y + \frac{2 x z - yz}{3} + x^{2} + \frac{y ^{2}}{4} + \frac{z ^{2}}{9}

c^{1} (x - 3)^{2}

c^{4} - 4 d^{4}

lo g_{10} (x^{3}) sin (x)

77 x^{4} - 72 x^{2} - 77

(2 x - 3 y - 4 z)^{3}

What is (x-1/2 y+1/3 z)^2 ?
The solution to (x-1/2 y+1/3 z)^2 is -xy+(2xz-yz)/3+x^2+(y^2)/4+(z^2)/9