erweitern (0.5x^2y^3+0.7a^2b^2)^2

Lösung

erweitern

(0.5 x^{2} y^{3} + 0.7 a^{2} b^{2})^{2}

0.25 x^{4} y^{6} + 0.7 x^{2} y^{3} a^{2} b^{2} + 0.49 a^{4} b^{4}

Schritte zur Lösung

(0.5 x^{2} y^{3} + 0.7 a^{2} b^{2})^{2}

Wende Formel für perfekte quadratische Gleichungen an:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(0.5 x^{2} y^{3} + 0.7 a^{2} b^{2})^{2} = (0.5 x^{2} y^{3})^{2} + 2 \cdot 0.5 x^{2} y^{3} \cdot 0.7 a^{2} b^{2} + (0.7 a^{2} b^{2})^{2}

= (0.5 x^{2} y^{3})^{2} + 2 \cdot 0.5 x^{2} y^{3} \cdot 0.7 a^{2} b^{2} + (0.7 a^{2} b^{2})^{2}

Vereinfache

(0.5 x^{2} y^{3})^{2} + 2 \cdot 0.5 x^{2} y^{3} \cdot 0.7 a^{2} b^{2} + (0.7 a^{2} b^{2})^{2} : 0.25 x^{4} y^{6} + 0.7 x^{2} y^{3} a^{2} b^{2} + 0.49 a^{4} b^{4}

= 0.25 x^{4} y^{6} + 0.7 x^{2} y^{3} a^{2} b^{2} + 0.49 a^{4} b^{4}

s im pl i f y \frac{a ^{3}}{7} + 0.999999 + \frac{3}{14}

s im pl i f y x^{0} + y^{0}

s im pl i f y x - i^{- 1} y

s im pl i f y (- 24) y (53)

s im pl i f y \frac{( x ^{3} - 5 x + 6 )}{( - 8 a ^{2} b ^{2} )}