化简 (1+(d^2)/5+6 d/5)^{-1}

解答

化简

(1 + \frac{d ^{2}}{5} + 6 \frac{d}{5})^{- 1}

\frac{5}{5 + d ^{2} + 6 d}

求解步骤

(1 + \frac{d ^{2}}{5} + 6 \cdot \frac{d}{5})^{- 1}

使用指数法则:

a^{- 1} = \frac{1}{a}

(1 + \frac{d ^{2}}{5} + 6 \cdot \frac{d}{5})^{- 1} = \frac{1}{1 + \frac{d ^{2}}{5} + 6 \cdot \frac{d}{5}}

= \frac{1}{1 + \frac{d ^{2}}{5} + 6 \cdot \frac{d}{5}}

化简

\frac{1}{1 + \frac{d ^{2}}{5} + 6 \cdot \frac{d}{5}} : \frac{5}{5 + d ^{2} + 6 d}

= \frac{5}{5 + d ^{2} + 6 d}

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