What is ((3x^2*y^3-5a^2*x^4))/((-3x^2)) ?

The solution to ((3x^2*y^3-5a^2*x^4))/((-3x^2)) is -(3y^3-5a^2x^2)/3

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simplify ((3x^2y^3-5a^2x^4))/((-3x^2))

simplify

\frac{( 3 x ^{2} \cdot y ^{3} - 5 a ^{2} \cdot x ^{4} )}{( - 3 x ^{2} )}

- \frac{3 y ^{3} - 5 a ^{2} x ^{2}}{3}

Solution steps

\frac{3 x ^{2} y ^{3} - 5 a ^{2} x ^{4}}{- 3 x ^{2}}

Factor out common term

x^{2} : x^{2} (3 y^{3} - 5 a^{2} x^{2})

= \frac{x ^{2} ( 3 y ^{3} - 5 a ^{2} x ^{2} )}{- 3 x ^{2}}

Cancel the common factor:

x^{2}

= \frac{3 y ^{3} - 5 a ^{2} x ^{2}}{- 3}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{3 y ^{3} - 5 a ^{2} x ^{2}}{3}

\frac{tan ( x )}{tan ^{2} ( x )}

(1 + x) 3

(1 + x) 6

a^{4} + 5 a^{2} + 6

(x - 5 x^{2})^{3}

What is ((3x^2*y^3-5a^2*x^4))/((-3x^2)) ?
The solution to ((3x^2*y^3-5a^2*x^4))/((-3x^2)) is -(3y^3-5a^2x^2)/3