solvefor a,a(r)=sqrt(r)*(e^r)^3+9

解答

求解

a, a (r) = r \cdot (e^{r})^{3} + 9

a = \frac{e ^{3 r} r + 9}{r}; r \neq = 0

求解步骤

a (r) = r (e^{r})^{3} + 9

化简

r (e^{r})^{3} + 9 : e^{3 r} r + 9

a r = e^{3 r} r + 9

两边除以

r; r \neq = 0

a = \frac{e ^{3 r} r + 9}{r}; r \neq = 0

3 x + c + 1 = 0

t (n) = t (n - 1) + n (n - 1)

so l v e f or a, x = (1 + a + b + c)

- 32 = - 7 u + 3 (u + 8)

so l v e f or x, 0 = 7 x - y + 13