What is the answer to ((x+a))/a-((x+b))/b =1 ?

The answer to ((x+a))/a-((x+b))/b =1 is x=(ab)/(-a+b);\quad ab\ne 0,a\ne b

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((x+a))/a-((x+b))/b =1

\frac{( x + a )}{a} - \frac{( x + b )}{b} = 1

x = \frac{ab}{- a + b}; ab \neq = 0, a \neq = b

Solution steps

\frac{( x + a )}{a} - \frac{( x + b )}{b} = 1

\frac{x + a}{a} - \frac{x + b}{b} = 1

Multiply by LCM

b (x + a) - a (x + b) = ab; ab \neq = 0

Expand

b (x + a) - a (x + b) : - a x + b x

- a x + b x = ab; ab \neq = 0

Factor

- a x + b x : x (- a + b)

x (- a + b) = ab; ab \neq = 0

Divide both sides by

- a + b; ab \neq = 0, a \neq = b

x = \frac{ab}{- a + b}; ab \neq = 0, a \neq = b

x, 3 k = 2 x - 1

x, x (1 + p^{2}) = 1

\frac{5}{1} - \frac{1}{3} \frac{x}{1} = 15

x, y - 6 = 9 x - 30

\frac{x}{0.25} - \frac{x}{0.5} - \frac{\frac{x}{1}}{4} = - 137

What is the answer to ((x+a))/a-((x+b))/b =1 ?
The answer to ((x+a))/a-((x+b))/b =1 is x=(ab)/(-a+b);\quad ab\ne 0,a\ne b