z=((2-2i))/((2+2i))

Lösung

z = \frac{( 2 - 2 i )}{( 2 + 2 i )}

z = - i

Schritte zur Lösung

z = \frac{( 2 - 2 i )}{( 2 + 2 i )}

Vereinfache

\frac{2 - 2 i}{2 + 2 i} : - i

z = - i

so l v e f or x, 5 x + 4 y = 42

73 x + 1 = 5 x + 10

lo g_{2} (1) (\frac{1}{2}) = x

x + (\frac{x - 21}{2}) + (\frac{x + 73}{4}) = \frac{483}{4}

so l v e f or x, 5 y + (- 9) x = 163