What is the answer to solvefor a,(a+b+c)(a-b+c)=a^2+b^2+c^2 ?

The answer to solvefor a,(a+b+c)(a-b+c)=a^2+b^2+c^2 is a=(b^2)/c ;\quad c\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor a,(a+b+c)(a-b+c)=a^2+b^2+c^2

solve for

a, (a + b + c) (a - b + c) = a^{2} + b^{2} + c^{2}

a = \frac{b ^{2}}{c}; c \neq = 0

Solution steps

(a + b + c) (a - b + c) = a^{2} + b^{2} + c^{2}

Expand

(a + b + c) (a - b + c) : - b^{2} + a^{2} + 2 a c + c^{2}

- b^{2} + a^{2} + 2 a c + c^{2} = a^{2} + b^{2} + c^{2}

Move

b^{2}

to the right side

a^{2} + 2 a c + c^{2} = 2 b^{2} + a^{2} + c^{2}

Move

c^{2}

to the right side

a^{2} + 2 a c = 2 b^{2} + a^{2}

Move

a^{2}

to the left side

2 a c = 2 b^{2}

Divide both sides by

2 c; c \neq = 0

a = \frac{b ^{2}}{c}; c \neq = 0

x, 192 x + 39 y = 3

5 + 2 (x - 8) + x = - 16

g, x^{9} + x^{5} + x^{4} + 2 = 2 g

2.7! = \frac{( k + 3 )}{8 !}

x, x - 7 y + 42 = 0

What is the answer to solvefor a,(a+b+c)(a-b+c)=a^2+b^2+c^2 ?
The answer to solvefor a,(a+b+c)(a-b+c)=a^2+b^2+c^2 is a=(b^2)/c ;\quad c\ne 0