solvefor x,y^1+y+y^2*(sin(x)-cos(x))=0

Solución

resolver para

x, y^{1} + y + y^{2} \cdot (sin (x) - cos (x)) = 0

x = arcsin (- \frac{2}{y}) + 2 πn + \frac{π}{4}, x = π + arcsin (\frac{2}{y}) + 2 πn + \frac{π}{4}

Pasos de solución

y^{1} + y + y^{2} (sin (x) - cos (x)) = 0

Re-escribir usando identidades trigonométricas

y + y^{1} + y^{2} 2 sin (x - \frac{π}{4}) = 0

Aplicar la regla

a^{1} = a

y^{1} = y

y + y + 2 y^{2} sin (x - \frac{π}{4}) = 0

Sumar elementos similares:

y + y = 2 y

2 y + 2 y^{2} sin (x - \frac{π}{4}) = 0

Mover

2 y

al lado derecho

2 y^{2} sin (x - \frac{π}{4}) = - 2 y

Dividir ambos lados entre

2 y^{2}; y \neq = 0

sin (x - \frac{π}{4}) = - \frac{2}{y}; y \neq = 0

Aplicar propiedades trigonométricas inversas

x - \frac{π}{4} = arcsin (- \frac{2}{y}) + 2 πn, x - \frac{π}{4} = π + arcsin (\frac{2}{y}) + 2 πn

Resolver

x - \frac{π}{4} = arcsin (- \frac{2}{y}) + 2 πn : x = arcsin (- \frac{2}{y}) + 2 πn + \frac{π}{4}

Resolver

x - \frac{π}{4} = π + arcsin (\frac{2}{y}) + 2 πn : x = π + arcsin (\frac{2}{y}) + 2 πn + \frac{π}{4}

x = arcsin (- \frac{2}{y}) + 2 πn + \frac{π}{4}, x = π + arcsin (\frac{2}{y}) + 2 πn + \frac{π}{4}

x - \frac{1}{10} = 997.5

x, e^{f} (x) + f - x = 1

x, \frac{x}{2} + \frac{( 3 y )}{5} = - 1

a, 160 a + 100 b = 64

a, 72.48 = a (24 + \frac{b}{100})