f_{2}=9n,f_{1}=6n

解答

f_{2} = 9 n, f_{1} = 6 n

n = \frac{f _{2}}{9}

求解步骤

f_{2} = 9 n

交换两边

9 n = f_{2}

两边除以

9

n = \frac{f _{2}}{9}

\frac{11}{25} = x \cdot 18 \cdot 10065 + 32 + 64 + 18 x

so l v e f or x, 1 = 10 - 3 e t^{2} - 2 x

x - \frac{x}{5} - \frac{( 2 x )}{3} = 2

x = 3 - 8, (x - \frac{2}{x})^{2}

so l v e f or x, 3 x - y + 5 + (2 x - 3 y - 4) = 0