solvefor a,a-a-2d-a-1d=23

解答

求解

a, a - a - 2 d - a - 1 d = 23

a = - 23 - 3 d

求解步骤

a - a - 2 d - a - 1 \cdot d = 23

对同类项分组

a - a - a - 2 d - 1 \cdot d = 23

b = \frac{( \frac{3}{20} + \frac{1}{2} + \frac{1}{15} )}{( \frac{31}{3} + \frac{2}{9} )}

so l v e f or x, 5 x + 6 y = 17.25

so l v e f or x, 17 x + 2 y = 36

\frac{5}{6} + x = \frac{3}{4} - (\frac{1}{3}) + \frac{4}{5}

so l v e f or x, 2 x + 3 y + 15 = 0