x+(k-1)*k-2(k+1)=0

解答

x + (k - 1) \cdot k - 2 (k + 1) = 0

x = - k^{2} + 3 k + 2

求解步骤

x + (k - 1) k - 2 (k + 1) = 0

将

(k - 1) \cdot k

到右边

x - 2 (k + 1) = - k (k - 1)

将

2 (k + 1)

到右边

x = - k^{2} + 3 k + 2

so l v e f or x, \frac{( x + p )}{q} - 1 = \frac{( x - q )}{p} + 1

so l v e f or g, c = g + 11

so l v e f or x, (y - 5) = 6 (x + 3)

- 2 x - 4 = 1

\frac{( a ) ( 2 x - 3 )}{3 + 13} = 4 x - 8