solvefor a,((1+i)^{75})/((1-i)^{72)}=a+b

解答

求解

a, \frac{( 1 + i ) ^{75}}{( 1 - i ) ^{72}} = a + b

a = \frac{( 1 + i ) ^{75}}{( 1 - i ) ^{72}} - b

求解步骤

\frac{( 1 + i ) ^{75}}{( 1 - i ) ^{72}} = a + b

交换两边

a + b = \frac{( 1 + i ) ^{75}}{( 1 - i ) ^{72}}

将

b

到右边

a = \frac{( 1 + i ) ^{75}}{( 1 - i ) ^{72}} - b

so l v e f or x, y = x + p^{3}

5 (\frac{- 11 - 5 b}{2}) + 2 = 4 b - 1

so l v e f or x, 7 x - 10 z = 9

(x - 9) + (5 x + 3) = 180

so l v e f or a, 45 a + 6 b^{4} = 1098