t(t)=t^2+5t+6

解答

t (t) = t^{2} + 5 t + 6

t = - \frac{6}{5}

十进制

t = - 1.2

求解步骤

t (t) = t^{2} + 5 t + 6

化简

t (t) : t^{2}

t^{2} = t^{2} + 5 t + 6

两边减去

t^{2} + 5 t

t^{2} - (t^{2} + 5 t) = t^{2} + 5 t + 6 - (t^{2} + 5 t)

化简

- 5 t = 6

两边除以

- 5

t = - \frac{6}{5}

so l v e f or x, 13 x + 14 y - 9 = 0

so l v e f or c, \frac{114982}{3} \cdot c \cdot m^{3} = \frac{4}{3} \cdot \frac{22}{7} \cdot r^{3}

so l v e f or x, (f) + 4 f = x - 2

so l v e f or g, g (s) = k (s + 2) (s^{2} - 4 s + 13)

so l v e f or x, 2 x^{1} - m (x - 1) = 0