What is the answer to (a^2-9)*x=a^9+27 ?

The answer to (a^2-9)*x=a^9+27 is x=(a^9+27)/(a^2-9);\quad a\ne 3,a\ne-3

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(a^2-9)*x=a^9+27

(a^{2} - 9) \cdot x = a^{9} + 27

x = \frac{a ^{9} + 27}{a ^{2} - 9}; a \neq = 3, a \neq = - 3

Solution steps

(a^{2} - 9) x = a^{9} + 27

Divide both sides by

a^{2} - 9; a \neq = 3, a \neq = - 3

x = \frac{a ^{9} + 27}{a ^{2} - 9}; a \neq = 3, a \neq = - 3

1 + 2 j + 21 b = - i - j - k, a = 2

x, f [g] + g [f] + 10 = 0

x, 42 t x t = 2125

\frac{4 + 2 x}{3 - 2} = \frac{x}{5}

x, 2 x y - 3 x + 5 y = 39

What is the answer to (a^2-9)*x=a^9+27 ?
The answer to (a^2-9)*x=a^9+27 is x=(a^9+27)/(a^2-9);\quad a\ne 3,a\ne-3