solvefor f,x(x^3-1)*f=1

解

解く

f, x (x^{3} - 1) \cdot f = 1

f = \frac{1}{x ( x ^{3} - 1 )}; x \neq = 0, x \neq = 1, x \neq = - \frac{1}{2} + i \frac{3}{2}, x \neq = - \frac{1}{2} - i \frac{3}{2}

解答ステップ

x (x^{3} - 1) f = 1

以下で両辺を割る

x (x^{3} - 1); x \neq = 0, x \neq = 1, x \neq = - \frac{1}{2} + i \frac{3}{2}, x \neq = - \frac{1}{2} - i \frac{3}{2}

f = \frac{1}{x ( x ^{3} - 1 )}; x \neq = 0, x \neq = 1, x \neq = - \frac{1}{2} + i \frac{3}{2}, x \neq = - \frac{1}{2} - i \frac{3}{2}