solvefor f,x(x^3-1)*f=1

解答

求解

f, x (x^{3} - 1) \cdot f = 1

f = \frac{1}{x ( x ^{3} - 1 )}; x \neq = 0, x \neq = 1, x \neq = - \frac{1}{2} + i \frac{3}{2}, x \neq = - \frac{1}{2} - i \frac{3}{2}

求解步骤

x (x^{3} - 1) f = 1

两边除以

x (x^{3} - 1); x \neq = 0, x \neq = 1, x \neq = - \frac{1}{2} + i \frac{3}{2}, x \neq = - \frac{1}{2} - i \frac{3}{2}

f = \frac{1}{x ( x ^{3} - 1 )}; x \neq = 0, x \neq = 1, x \neq = - \frac{1}{2} + i \frac{3}{2}, x \neq = - \frac{1}{2} - i \frac{3}{2}

\frac{( 5 x - 1 )}{4} - \frac{( 3 x - 1 )}{6} = \frac{32}{3}

so l v e f or x, \frac{x}{9} = \frac{3}{y} + \frac{1}{18}

so l v e f or x, 8! = 3 x + 3 y

so l v e f or x, 12 x - 3 \frac{y}{7} a = \frac{1}{a} - 13

so l v e f or a, 600 = a + b^{2} + c^{3}