What are the solutions to the equation 25y^3-36y=0 ?

The solutions to the equation 25y^3-36y=0 are y=0,y=-6/5 ,y= 6/5

Find the zeros of 25y^3-36y=0

The zeros of 25y^3-36y=0 are y=0,y=-6/5 ,y= 6/5

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25 y^{3} - 36 y = 0

y = 0, y = - \frac{6}{5}, y = \frac{6}{5}

Decimal Notation

y = 0, y = - 1.2, y = 1.2

Solution steps

25 y^{3} - 36 y = 0

Factor

25 y^{3} - 36 y : y (5 y + 6) (5 y - 6)

y (5 y + 6) (5 y - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 5 y + 6 = 0 or 5 y - 6 = 0

Solve

5 y + 6 = 0 : y = - \frac{6}{5}

Solve

5 y - 6 = 0 : y = \frac{6}{5}

The solutions are

y = 0, y = - \frac{6}{5}, y = \frac{6}{5}

2 = (1 + x)^{10}

n^{3} - n = 720

x^{3} - 9 x^{2} + 3 x + 45 = 0

(x^{2} - 1) (x^{2} - 11) (x^{2} - 21) (x^{2} - 31) = - 4224

(3 x + 1)^{3} = 100

What are the solutions to the equation 25y^3-36y=0 ?
The solutions to the equation 25y^3-36y=0 are y=0,y=-6/5 ,y= 6/5
Find the zeros of 25y^3-36y=0
The zeros of 25y^3-36y=0 are y=0,y=-6/5 ,y= 6/5