解答
2+6−1=x16−4
解答
x=811,x=−811,x=811i,x=−811i,x=21611+24411i,x=−21611−24411i,x=−21611+24411i,x=21611−24411i,x=22−21611+2811(2−2)i,x=−22−21611−2811(2−2)i,x=−22+21611+2811(2+2)i,x=22+21611−2811(2+2)i,x=22+21611+2811(2+2)i,x=−22+21611−2811(2+2)i,x=−22−21611+2811(2−2)i,x=22−21611−2811(2−2)i
求解步骤
2+6−1=x16−4
交换两边x16−4=2+6−1
将 4到右边
x16=11
用u=x2 和 u8=x16改写方程式u8=11
解 u8=11:u=411,u=−411,u=411i,u=−411i,u=2811+2411i,u=−2811−2411i,u=−2811+2411i,u=2811−2411i
u=411,u=−411,u=411i,u=−411i,u=2811+2411i,u=−2811−2411i,u=−2811+2411i,u=2811−2411i
代回 u=x2，求解 x
解 x2=411:x=811,x=−811
解 x2=−411:x=811i,x=−811i
解 x2=411i:x=21611+24411i,x=−21611−24411i
解 x2=−411i:x=−21611+24411i,x=21611−24411i
解 x2=2811+2411i:x=22−21611+2811(2−2)i,x=−22−21611−2811(2−2)i
解 x2=−2811−2411i:x=−22+21611+2811(2+2)i,x=22+21611−2811(2+2)i
解 x2=−2811+2411i:x=22+21611+2811(2+2)i,x=−22+21611−2811(2+2)i
解 x2=2811−2411i:x=−22−21611+2811(2−2)i,x=22−21611−2811(2−2)i
解为
x=811,x=−811,x=811i,x=−811i,x=21611+24411i,x=−21611−24411i,x=−21611+24411i,x=21611−24411i,x=22−21611+2811(2−2)i,x=−22−21611−2811(2−2)i,x=−22+21611+2811(2+2)i,x=22+21611−2811(2+2)i,x=22+21611+2811(2+2)i,x=−22+21611−2811(2+2)i,x=−22−21611+2811(2−2)i,x=22−21611−2811(2−2)i