sqrt(2)*x^2-3x-2sqrt(2)=0

解答

2 \cdot x^{2} - 3 x - 22 = 0

x = 22, x = - \frac{1}{2}

十进制

x = 2.82842 \dots, x = - 0.70710 \dots

求解步骤

2 x^{2} - 3 x - 22 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 2 ( - 2 2 )}{2 2}

(- 3)^{2} - 42 (- 22) = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 2}

将解分隔开

x_{1} = \frac{- ( - 3 ) + 5}{2 2}, x_{2} = \frac{- ( - 3 ) - 5}{2 2}

x = \frac{- ( - 3 ) + 5}{2 2} : 22

x = \frac{- ( - 3 ) - 5}{2 2} : - \frac{1}{2}

二次方程组的解是:

x = 22, x = - \frac{1}{2}

(3 x - 1)^{2} - (2 x + 3)^{2} = 0

(x - a)^{2} = b

so l v e f or y, y (y + 1) = x (x + 1) (x + 2)

3 m^{2} + 2 = 4, m^{2} + 23 m^{2} - 4 m^{2} = 2 - 2

2 x^{2} - 5 x + 2 = 0, x - 2 \geq 0