0.2x^2+1.2x-32=0

解

0.2 x^{2} + 1.2 x - 32 = 0

x = 10, x = - 16

解答ステップ

0.2 x^{2} + 1.2 x - 32 = 0

以下で両辺を乗じる:

10

2 x^{2} + 12 x - 320 = 0

解くとthe二次式

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 ( - 320 )}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 (- 320) = 52

x_{1, 2} = \frac{- 12 \pm 52}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 12 + 52}{2 \cdot 2}, x_{2} = \frac{- 12 - 52}{2 \cdot 2}

x = \frac{- 12 + 52}{2 \cdot 2} : 10

x = \frac{- 12 - 52}{2 \cdot 2} : - 16

二次equationの解:

x = 10, x = - 16