x^2+x-12=0,x^1=3x^2=-4

解

x^{2} + x - 12 = 0, x^{1} = 3 x^{2} = - 4

x = 3, x = - 4

解答ステップ

x^{2} + x - 12 = 0

解くとthe二次式

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 1 + 7}{2 \cdot 1}, x_{2} = \frac{- 1 - 7}{2 \cdot 1}

x = \frac{- 1 + 7}{2 \cdot 1} : 3

x = \frac{- 1 - 7}{2 \cdot 1} : - 4

二次equationの解:

x = 3, x = - 4