solvefor x,p^2-y^2*q=x^2-y^2

解

解く

x, p^{2} - y^{2} \cdot q = x^{2} - y^{2}

x = p^{2} - y^{2} q + y^{2}, x = - p^{2} - y^{2} q + y^{2}

解答ステップ

p^{2} - y^{2} q = x^{2} - y^{2}

辺を交換する

x^{2} - y^{2} = p^{2} - y^{2} q

y^{2}

を右側に移動します

x^{2} = p^{2} - y^{2} q + y^{2}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

x = p^{2} - y^{2} q + y^{2}, x = - p^{2} - y^{2} q + y^{2}