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受欢迎的代数 >

5t^2-2t-1=0

解答

5 t^{2} - 2 t - 1 = 0

解答

t = \frac{1 + 6}{5}, t = \frac{1 - 6}{5}

+1

十进制

t = 0.68989 \dots, t = - 0.28989 \dots

求解步骤

5 t^{2} - 2 t - 1 = 0

使用求根公式求解

t_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 (- 1) = 26

t_{1, 2} = \frac{- ( - 2 ) \pm 2 6}{2 \cdot 5}

将解分隔开

t_{1} = \frac{- ( - 2 ) + 2 6}{2 \cdot 5}, t_{2} = \frac{- ( - 2 ) - 2 6}{2 \cdot 5}

t = \frac{- ( - 2 ) + 2 6}{2 \cdot 5} : \frac{1 + 6}{5}

t = \frac{- ( - 2 ) - 2 6}{2 \cdot 5} : \frac{1 - 6}{5}

二次方程组的解是:

t = \frac{1 + 6}{5}, t = \frac{1 - 6}{5}

作图

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