3^{2x+1}=5^{2x+1}

Lösung

3^{2 x + 1} = 5^{2 x + 1}

x = - \frac{1}{2}

Dezimale

x = - 0.5

Schritte zur Lösung

3^{2 x + 1} = 5^{2 x + 1}

Wende Exponentenregel an

(2 x + 1) ln (3) = (2 x + 1) ln (5)

Löse

(2 x + 1) ln (3) = (2 x + 1) ln (5) : x = - \frac{1}{2}

x = - \frac{1}{2}

1 0^{x} = - 2

6^{5 x} = 27

100000 = 1 0^{x}

16 = 8^{x + 5}

4^{x} + 3 \cdot 2^{x - 1} - 1 = 0