11^{-3x}=17^{x-6}

Lösung

1 1^{- 3 x} = 1 7^{x - 6}

x = \frac{6 ln ( 17 )}{3 ln ( 11 ) + ln ( 17 )}

Dezimale

x = 1.69536 \dots

Schritte zur Lösung

1 1^{- 3 x} = 1 7^{x - 6}

Wende Exponentenregel an

- 3 x ln (11) = (x - 6) ln (17)

Löse

- 3 x ln (11) = (x - 6) ln (17) : x = \frac{6 ln ( 17 )}{3 ln ( 11 ) + ln ( 17 )}

x = \frac{6 ln ( 17 )}{3 ln ( 11 ) + ln ( 17 )}

7^{x + 2} + 7^{x + 1} = 8

12000 = 200 e^{0.01 t}

2^{x - 2} = 4^{2021}

3^{x} + 3^{x + 1} = 36

3^{x} - 0.5 = 0