9^{x+3}=27^{x-1}

Lösung

9^{x + 3} = 2 7^{x - 1}

x = 9

Schritte zur Lösung

9^{x + 3} = 2 7^{x - 1}

Wende Exponentenregel an

2 (x + 3) = 3 (x - 1)

Löse

2 (x + 3) = 3 (x - 1) : x = 9

x = 9

- 2 \cdot (- 2)^{n - 1} = (- 2)^{n}

(5^{x - 3}) (3^{2 x - 8}) = 225

2 = a^{x}

so l v e f or x, 2^{x} + 2^{y} = 2^{y} + 4^{x}

3^{x - 3} = 2 x - 5