27^x=(1/3)^{-3}

Lösung

2 7^{x} = (\frac{1}{3})^{- 3}

x = 1

Schritte zur Lösung

2 7^{x} = (\frac{1}{3})^{- 3}

Wende Exponentenregel an

3 x = 3

Löse

3 x = 3 : x = 1

x = 1

3^{4 x + 4} + 3^{4 x} = 3^{5}

3^{2 x + 2} + 3^{2 x + 1} = 108

4 9^{n - 1} + 6 = 7^{2 n - 1}

(125)^{x + 4} = 5

2 = (\frac{9}{8})^{t}