4^{3x}=32^{x-1}

Lösung

4^{3 x} = 3 2^{x - 1}

x = - 5

Schritte zur Lösung

4^{3 x} = 3 2^{x - 1}

Wende Exponentenregel an

6 x = 5 (x - 1)

Löse

6 x = 5 (x - 1) : x = - 5

x = - 5

2 5^{x - 1} + 100 = 5^{2 x - 1}

2^{2 x + 1} = 2^{x + 2}

6^{x + 2} = 1 3^{9 x}

2^{2 x + 5} - 7 (2^{x}) = 0

2^{x + 1} + 2^{2 x} = 80