d^2-4d+4=2^x

Lösung

d^{2} - 4 d + 4 = 2^{x}

x = \frac{ln ( d ^{2} - 4 d + 4 )}{ln ( 2 )}

Schritte zur Lösung

d^{2} - 4 d + 4 = 2^{x}

Wende Exponentenregel an

ln (d^{2} - 4 d + 4) = x ln (2)

Löse

ln (d^{2} - 4 d + 4) = x ln (2) : x = \frac{ln ( d ^{2} - 4 d + 4 )}{ln ( 2 )}

x = \frac{ln ( d ^{2} - 4 d + 4 )}{ln ( 2 )}

(60.431)^{a} = 1 0^{e}

2^{x + 5} = 2^{x + 3} + 6

1 0^{8} = 1 0^{w}

so l v e f or m, 2^{m} + 2^{n} = 2^{m} + n

2^{3} = 3^{x}