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受欢迎的代数 >

solvefor a, 1/a+1/b+1/c = 37/48

解答

求解

a, \frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{37}{48}

解答

a = - \frac{48 b c}{48 c + 48 b - 37 b c}; b \neq = - \frac{48 c}{48 - 37 c}

求解步骤

\frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{37}{48}

乘以最小公倍数

48 b c + 48 a c + 48 ab = 37 ab c

将

48 b c

到右边

48 a c + 48 ab = 37 ab c - 48 b c

将

37 ab c

para o lado esquerdo

48 a c + 48 ab - 37 ab c = - 48 b c

分解

48 a c + 48 ab - 37 ab c : a (48 c + 48 b - 37 b c)

a (48 c + 48 b - 37 b c) = - 48 b c

两边除以

48 c + 48 b - 37 b c; b \neq = - \frac{48 c}{48 - 37 c}

a = - \frac{48 b c}{48 c + 48 b - 37 b c}; b \neq = - \frac{48 c}{48 - 37 c}

作图

流行的例子

1/(2*y^2)=7y-12

\frac{1}{2 \cdot y ^{2}} = 7 y - 12

9 = \frac{v + 4}{v + 12}

solvefor x,g=x+f((x))/x*3

so l v e f or x, g = x + f \frac{( x )}{x} \cdot 3

solvefor b,a= 1/((b-c))

so l v e f or b, a = \frac{1}{( b - c )}

x=(log_{10}(109))/x

x = \frac{lo g _{10} ( 109 )}{x}