solvefor y,3x^2y^4=5x^3y^{-3}z^2

解答

求解

y, 3 x^{2} y^{4} = 5 x^{3} y^{- 3} z^{2}

y = 7 \frac{5 x z ^{2}}{3}; x \neq = 0

求解步骤

3 x^{2} y^{4} = 5 x^{3} y^{- 3} z^{2}

整理后得

3 x^{2} y^{4} = \frac{5 x ^{3} z ^{2}}{y ^{3}}

在两边乘以

y^{3}

3 y^{7} x^{2} = 5 x^{3} z^{2}

解

3 y^{7} x^{2} = 5 x^{3} z^{2} : y = 7 \frac{5 x z ^{2}}{3}; x \neq = 0

y = 7 \frac{5 x z ^{2}}{3}; x \neq = 0

\frac{( 1 + x ^{4} + x ^{8} )}{x ^{4}} = 4

\frac{2 ( x + 1 )}{3 + 4 ( x - 2 )} = \frac{x}{2 + 5}

\frac{3 x - 2}{x} = \frac{59 x ^{2} - 4}{x ^{2}}

(\frac{x + 1}{x})^{2} - 2 (\frac{x - 1}{x + 4}) - 11 = 0

\frac{21}{2 \cdot x} = \frac{331}{3}