solvefor l,z=((1+l))/(((3+l)^2))

解

解く

l, z = \frac{( 1 + l )}{( ( 3 + l ) ^{2} )}

l = \frac{- 6 z + 1 + - 8 z + 1}{2 z}, l = \frac{- 6 z + 1 - - 8 z + 1}{2 z}; z \neq = 0

解答ステップ

z = \frac{( 1 + l )}{( ( 3 + l ) ^{2} )}

簡素化

\frac{( 1 + l )}{( ( 3 + l ) ^{2} )} : \frac{1 + l}{( 3 + l ) ^{2}}

z = \frac{1 + l}{( 3 + l ) ^{2}}

以下で両辺を乗じる:

(3 + l)^{2}

z (3 + l)^{2} = 1 + l

解く

z (3 + l)^{2} = 1 + l : l = \frac{- 6 z + 1 + - 8 z + 1}{2 z}, l = \frac{- 6 z + 1 - - 8 z + 1}{2 z}; z \neq = 0

l = \frac{- 6 z + 1 + - 8 z + 1}{2 z}, l = \frac{- 6 z + 1 - - 8 z + 1}{2 z}; z \neq = 0