solvefor s,1+(k_{c})/(((2s+1)(5s+1)))=0

解

解く

s, 1 + \frac{k _{c}}{( ( 2 s + 1 ) ( 5 s + 1 ) )} = 0

s = \frac{- 7 + - 40 k _{c} + 9}{20}, s = \frac{- 7 - - 40 k _{c} + 9}{20}

解答ステップ

1 + \frac{k _{c}}{( ( 2 s + 1 ) ( 5 s + 1 ) )} = 0

簡素化

\frac{k _{c}}{( ( 2 s + 1 ) ( 5 s + 1 ) )} : \frac{k _{c}}{( 2 s + 1 ) ( 5 s + 1 )}

1 + \frac{k _{c}}{( 2 s + 1 ) ( 5 s + 1 )} = 0

以下で両辺を乗じる:

(2 s + 1) (5 s + 1)

(2 s + 1) (5 s + 1) + k_{c} = 0

解く

(2 s + 1) (5 s + 1) + k_{c} = 0 : s = \frac{- 7 + - 40 k _{c} + 9}{20}, s = \frac{- 7 - - 40 k _{c} + 9}{20}

s = \frac{- 7 + - 40 k _{c} + 9}{20}, s = \frac{- 7 - - 40 k _{c} + 9}{20}