What is the answer to (x^2+3x-20)/((x^2+3x))=8 ?

The answer to (x^2+3x-20)/((x^2+3x))=8 is x=-3/2-i(sqrt(119))/(14),x=-3/2+i(sqrt(119))/(14)

Solve for x: (x^2+3x-20)/((x^2+3x))=8

The solution is x=-3/2-i(sqrt(119))/(14),x=-3/2+i(sqrt(119))/(14)

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\frac{x ^{2} + 3 x - 20}{( x ^{2} + 3 x )} = 8

x = - \frac{3}{2} - i \frac{119}{14}, x = - \frac{3}{2} + i \frac{119}{14}

Solution steps

\frac{x ^{2} + 3 x - 20}{( x ^{2} + 3 x )} = 8

Simplify

\frac{x ^{2} + 3 x - 20}{( x ^{2} + 3 x )} : \frac{x ^{2} + 3 x - 20}{x ^{2} + 3 x}

\frac{x ^{2} + 3 x - 20}{x ^{2} + 3 x} = 8

Multiply both sides by

x^{2} + 3 x

x^{2} + 3 x - 20 = 8 (x^{2} + 3 x)

Solve

x^{2} + 3 x - 20 = 8 (x^{2} + 3 x) : x = - \frac{3}{2} - i \frac{119}{14}, x = - \frac{3}{2} + i \frac{119}{14}

x = - \frac{3}{2} - i \frac{119}{14}, x = - \frac{3}{2} + i \frac{119}{14}

\frac{a ^{3} x \cdot a ^{4} x}{( a ^{3} x ) 2} = 4 a

\frac{x ^{2} + 5}{x} = (- 3 - x)

\frac{6 a}{a ^{2} + 9} = 1

\frac{\frac{98}{9}}{y} = \frac{38}{27}

2 (\frac{x ^{2} + 1}{( x ^{2} )}) - 3 (\frac{x + 1}{x}) = 1

What is the answer to (x^2+3x-20)/((x^2+3x))=8 ?
The answer to (x^2+3x-20)/((x^2+3x))=8 is x=-3/2-i(sqrt(119))/(14),x=-3/2+i(sqrt(119))/(14)
Solve for x: (x^2+3x-20)/((x^2+3x))=8
The solution is x=-3/2-i(sqrt(119))/(14),x=-3/2+i(sqrt(119))/(14)