|2x-x^2-3x|=1

Lösung

2 x - x^{2} - 3 x = 1

x = - \frac{1 + 5}{2} or x = \frac{5 - 1}{2}

Dezimale

x = - 1.61803 \dots, x = 0.61803 \dots

Schritte zur Lösung

2 x - x^{2} - 3 x = 1

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

2 x - x^{2} - 3 x = - 1 or 2 x - x^{2} - 3 x = 1

2 x - x^{2} - 3 x = - 1 or 2 x - x^{2} - 3 x = 1

(x = - \frac{1 + 5}{2} or x = \frac{5 - 1}{2}) or keine L \overset{o}{¨} sung

x = - \frac{1 + 5}{2} or x = \frac{5 - 1}{2}

x^{2} - 2 + ∣ x - 1 ∣ = x^{2} - x - 1

∣ x - 3 ∣ - ∣ 2 x - 5 ∣ = 0

\frac{1}{2} x - \frac{2}{3} - 1 = \frac{1}{6}

∣ x - 3 ∣ + ∣ 3 - x ∣ = 1

∣ x + 1 ∣ = 2 x - 3