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受欢迎的代数 >

2.8=-log_{10}(h^{30})

解答

2.8 = - lo g_{10} (h^{30})

解答

h = \frac{1.62657 E 15}{2.5 E 15}, h = - \frac{1.62657 E 15}{2.5 E 15}

+1

十进制

h = 0.80661 \dots, h = - 0.80661 \dots

求解步骤

2.8 = - lo g_{10} (h^{30})

将

lo g_{10} (h^{30})

para o lado esquerdo

2.8 + lo g_{10} (h^{30}) = 0

将

2.8

到右边

lo g_{10} (h^{30}) = - 2.8

使用指数法则:

a^{2 \cdot n} = (a^{2})^{n}

h^{30} = (h^{2})^{15}

lo g_{10} ((h^{2})^{15}) = - 2.8

使用对数运算法则

h^{2} = \frac{1}{1 0 ^{0.18666 \dots}}

解

h^{2} = \frac{1}{1 0 ^{0.18666 \dots}} : h = \frac{1.62657 E 15}{2.5 E 15}, h = - \frac{1.62657 E 15}{2.5 E 15}

h = \frac{1.62657 E 15}{2.5 E 15}, h = - \frac{1.62657 E 15}{2.5 E 15}

验证解:

h = \frac{1.62657 E 15}{2.5 E 15}

真

, h = - \frac{1.62657 E 15}{2.5 E 15}

真

解为

h = \frac{1.62657 E 15}{2.5 E 15}, h = - \frac{1.62657 E 15}{2.5 E 15}

作图

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