What is x+3y=12,3x+2y=123 ?

The solution to x+3y=12,3x+2y=123 is x= 345/7 ,y=-87/7

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x+3y=12,3x+2y=123

x + 3 y = 12, 3 x + 2 y = 123

x = \frac{345}{7}, y = - \frac{87}{7}

Solution steps

[x + 3 y = 12 3 x + 2 y = 123]

Isolate

x

for

x + 3 y = 12 : x = 12 - 3 y

Substitute

x = 12 - 3 y

[3 (12 - 3 y) + 2 y = 123]

Simplify

[36 - 7 y = 123]

Isolate

y

for

36 - 7 y = 123 : y = - \frac{87}{7}

For

x = 12 - 3 y

Substitute

y = - \frac{87}{7}

x = 12 - 3 (- \frac{87}{7})

12 - 3 (- \frac{87}{7}) = \frac{345}{7}

x = \frac{345}{7}

The solutions to the system of equations are:

x = \frac{345}{7}, y = - \frac{87}{7}

7 x - 3 y = 31, 9 x - 5 y = 41

6 x + 4 y = 8, - x - 4 y = 12

x - 3 y = 1, 4 x - 5 y = 22

5 x + 2 y = 7, 2 x - 3 y = 18

2 b = 2, a = 1

What is x+3y=12,3x+2y=123 ?
The solution to x+3y=12,3x+2y=123 is x= 345/7 ,y=-87/7