zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

y^2=x+1,y=x-1

解答

y^{2} = x + 1, y = x - 1

解答

(x = 3, x = 0, y = 2 y = - 1)

求解步骤

[y^{2} = x + 1 y = x - 1]

方程式相减

y^{2} = x + 1

y^{2} - y = x + 1 - (x - 1)

化简

y^{2} - y = 2

解

y^{2} - y = 2 : y = 2, y = - 1

将解

y = 2, y = - 1

代入

y^{2} = x + 1

对于

y^{2} = x + 1

，用

2

替代

y : x = 3

对于

y^{2} = x + 1

，用

- 1

替代

y : x = 0

将解代入原方程进行验证

因而，

y^{2} = x + 1, y = x - 1

最后的解是

(x = 3, x = 0, y = 2 y = - 1)

作图

流行的例子

g(x)=2,x^2+x-1x=-1/2

g (x) = 2, x^{2} + x - 1 x = - \frac{1}{2}

f(x)=x^2-2x+3,f(x)=-2x+7

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x + 7

x + y - z = 4, y - z = 1

+ \frac{x}{8} x = 2 y, y = 3

(a^2)/x-(b^2)/y =0,a^2 b/x+b^2 a/y =a+b

\frac{a ^{2}}{x} - \frac{b ^{2}}{y} = 0, a^{2} \frac{b}{x} + b^{2} \frac{a}{y} = a + b