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受欢迎的代数 >

1/x+4/y = 2/7 , 4/3 x+1/2 y=-8/5

解答

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}, \frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}

解答

(x = \frac{21}{20}, x = - 4, y = - 6 y = \frac{112}{15})

求解步骤

[\frac{1}{x} + \frac{4}{y} = \frac{2}{7} \frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}]

对于

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}

将

x

移到一边:

x = - \frac{7 y}{2 ( 14 - y )}; y \neq = 14

将解

x = - \frac{7 y}{2 ( 14 - y )}

代入

\frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}

对于

\frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}

，用

- \frac{7 y}{2 ( 14 - y )}

替代

x : y = - 6, y = \frac{112}{15}

将解

y = - 6, y = \frac{112}{15}

代入

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}

对于

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}

，用

- 6

替代

y : x = \frac{21}{20}

对于

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}

，用

\frac{112}{15}

替代

y : x = - 4

将解代入原方程进行验证

因而，

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}, \frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}

最后的解是

(x = \frac{21}{20}, x = - 4, y = - 6 y = \frac{112}{15})

作图

流行的例子

f(x)(x)^1(x)=1,+xf(x)(x)^2(x)=x^2

f (x) (x)^{1} (x) = 1, + x f (x) (x)^{2} (x) = x^{2}

x+3y=13,x^2+3y^2=43

x + 3 y = 13, x^{2} + 3 y^{2} = 43

u(y,x)-9u(y,x)=(1/2)x^4,y=6

u (y, x) - 9 u (y, x) = (\frac{1}{2}) x^{4}, y = 6

0+1/2 yy=x+150,x=15

0 + \frac{1}{2} yy = x + 150, x = 15

x+y=12, 1/x+1/y =8

x + y = 12, \frac{1}{x} + \frac{1}{y} = 8