(x-2)*(x-4)>0

Lösung

(x - 2) \cdot (x - 4) > 0

x < 2 or x > 4

Intervall-Notation

(- \infty, 2) \cup (4, \infty)

Schritte zur Lösung

(x - 2) (x - 4) > 0

Identifiziere die Intervalle

x < 2 or x > 4

\frac{( 3 x - 1 )}{( x + 2 )} => 5

x^{3} - 6 x < 0

\frac{- 3}{( 2 x + 3 )} \geq 0

\frac{x}{( x - 1 )} < 0

(x + 1) (x - 4) < 0