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Beliebt Algebra >

1/((x+1)-1)>= (2-1)/((x-2))

Lösung

\frac{1}{( x + 1 ) - 1} \geq \frac{2 - 1}{( x - 2 )}

Lösung

0 < x < 2

+1

Intervall-Notation

(0, 2)

Schritte zur Lösung

\frac{1}{x + 1 - 1} \geq \frac{2 - 1}{x - 2}

Rewrite in standard form

\frac{1}{x ( x - 2 )} \leq 0

Wenn

\frac{1}{a} \leq 0

dann

a < 0

x (x - 2) < 0

Identifiziere die Intervalle

0 < x < 2

Graph

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