(10x-7)(x-5)<= 0

Lösung

(10 x - 7) (x - 5) \leq 0

\frac{7}{10} \leq x \leq 5

Intervall-Notation

[\frac{7}{10}, 5]

Dezimale

0.7 \leq x \leq 5

Schritte zur Lösung

(10 x - 7) (x - 5) \leq 0

Identifiziere die Intervalle

\frac{7}{10} \leq x \leq 5

- 3 x^{2} + 7 x + 6 > 0

2 x^{2} - x - 6 < 14

\frac{1}{( x ^{2} )} < 2

x (x - 3) (x - 1)^{2} < 0

\frac{( 3 x - 2 )}{( x - 1 )} \geq 0