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Beliebt Algebra >

4/((x+2))>= 3-x

Lösung

\frac{4}{( x + 2 )} \geq 3 - x

Lösung

- 2 < x \leq - 1 or x \geq 2

+1

Intervall-Notation

(- 2, - 1] \cup [2, \infty)

Schritte zur Lösung

\frac{4}{x + 2} \geq 3 - x

Rewrite in standard form

\frac{x ^{2} - x - 2}{x + 2} \geq 0

Faktorisiere

\frac{x ^{2} - x - 2}{x + 2} : \frac{( x + 1 ) ( x - 2 )}{x + 2}

\frac{( x + 1 ) ( x - 2 )}{x + 2} \geq 0

Identifiziere die Intervalle

- 2 < x \leq - 1 or x \geq 2

Graph

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