x^3+5x^2+4x>0

Lösung

x^{3} + 5 x^{2} + 4 x > 0

- 4 < x < - 1 or x > 0

Intervall-Notation

(- 4, - 1) \cup (0, \infty)

Schritte zur Lösung

x^{3} + 5 x^{2} + 4 x > 0

Faktorisiere

x^{3} + 5 x^{2} + 4 x : x (x + 1) (x + 4)

x (x + 1) (x + 4) > 0

Identifiziere die Intervalle

- 4 < x < - 1 or x > 0

m^{2} > 3

(x - 2)^{4} \leq 0

x^{2} \cdot (x - 5) (x - 2) \geq 0

(x + 5) (x - 3) < (x - 3)

\frac{1}{x ^{4}} \geq \frac{1}{16}